Question

When sodium reacts with water, sodium hydroxide and hydrogen are produced. The balanced equation for this reaction is:

If 6 moles of water react,

The reaction consumes	moles of sodium.
The reaction produces	moles of sodium hydroxide and
	moles of hydrogen.

Answer 1

Answer:

Step 1: Explanation:

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio can be determined by examining the coefficients in front of formulas in a balanced chemical equation.

Step 2: write the balanced chemical equation.

2 Na(s) + 2 H₂O(l) ---> 2 NaOH(aq) + H₂(g)

Step 3: Calculation of moles of sodium consumed

2 Na(s) + 2 H₂O(l) ---> 2 NaOH(aq) + H₂(g)

According to the reaction:

2 mol of  H₂O completely reacts with 2 mol of  Na

so, 6 mol of  H₂O will completely reacts with =( 2 mol of Na / 2 mol of  H₂O )× 6 mol of H₂O= 6  mol of  Na

Hence, moles of sodium consumed = 6 moles

Step 4: Calculation of  the moles of sodium hydroxide (NaOH) produced

2 Na(s) + 2 H₂O(l) ---> 2 NaOH(aq) + H₂(g)

According to the reaction:

2 mol of H₂O produced  2 mol of NaOH

so, 6 mol of H₂O will produce = ( 2 mol of NaOH / 2 mol of H₂O )× 6 mol of H₂O = 6 mol of  NaOH

Step 5: Calculation of  the moles of hydrogen (H₂) produced

2 Na(s) + 2 H₂O(l) ---> 2 NaOH(aq) + H₂(g)

According to the reaction:

2 mol of H₂O produced 1 mol of H₂

so, 6 mol of H₂O will produce = ( 1 mol of H₂ / 2 mol of H₂O )× 6 mol of H₂O = 3 mol of H₂

1. Moles of sodium(Na) consumed = 6 moles

2.Moles of Sodium hydroxide produced = 6 moles

3. Moles of Hydrogen produced = 3 moles