Spectral lines from a Seyfert galaxy are observed to be redshifted by 0.5 percent and to have broadened emission lines indicating an orbital speed of 250 km/s at an angular distance of 0.1" from its center. Assuming circular orbits, use Kepler's laws to estimate the mass within this 0.1" radius.
Here, we need to assume a Hubble constant to find d value
I am assuming as 75 Km/s/Mpc
so,
d = 20 Mpc
Now,
radius within 1'' area is given as
(0.1 / 360 * 3600 ) * d / 2
*20e6
solve for d, we get
d = 9.7 pc
we know
1 pc = 206265 AU
so,
d = 9.7 pc = 2e6 AU
Now, we need to find period
P = 2
r / v
P = 2
*2e6 * 1.48e11 /
250e3
(note that we need to convert AU to meters)
so,
P = 7.439e12 seconds
P = 2.36e5 Years
so,
Mass = d3 / P2 (from Kepler's third law)
Note that for Kepler's law to work fine, distance should be in AU and period should be in years.
Mass = 2e63 / 2.36e52
Mass = 1.44e8 solar masses
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