Question

a) According to the kinetic theory of gases, determine the mean speed of oxygen (MO2=32 kg/kmol) molecules at 500K and a pressure of 2 atm. (/3)










b) According to the kinetic theory of gases, what is the average distance between collisions of oxygen (MO2=32 kg/kmol, collision diameter=2.92Ǻ) molecules at 500 K and 2 atm? (/3)













c) According to the kinetic theory of gases, how many oxygen molecules would occupy a volume 10 m wide, 25 m deep and 3 m high? (/4)
d) If the most probable speed of the molecules in an unknown gas is 200 m/s, what is the mean squared-speed of the molecules at the same conditions, assuming ideal gas behaviour? (/4)

  

Answer 1

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Answer 1

The mean speed of oxygen is calculated by using formula :

V mean = (3RT/M)^1/2

= (3 × 8.314 j/mol k × 500 K / 32 Kg/mol × 10^-3 )^1/2

= 624.27 m/s ( Answer,)

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