Question

Mutual Inductance of a Double Solenoid

We will consider the field that arises from solenoid 1, whichhas n_1 turns per unit length. The magnetic field due to solenoid1 passes (entirely, in this case) through solenoid 2, which hasn_2 turns per unit length. Any change in magnetic flux fromthe field generated by solenoid 1induces an EMF in solenoid 2through Faraday's law of induction, oint vec{E}(vec{r}) cdot dvec{l} = - frac{d}{dt}Phi_{M}(t).39636B.jpgConsider first the generation of the magnetic field by thecurrent I_{1}(t) in solenoid 1. Within the solenoid (sufficientlyfar from its ends), what is themagnitude B_{1}(t) of the magnetic field due tothis current?
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Answer #1
A)B=μ0n1I1B)φ= BA=B1(t)*πρ2C)-n20*n1*(dI1/dt)*π*ρ2*LD)ε=-M21dI/dtE&F)μ0n2n1πρ2L
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