Calculate the DeltaG for the oxidation of H2 coupled to the reduction of O2.
H2 + 1/2 O2→ H2O
PLZ SHOW WORK
Using the thermodynamic data of energy:
∆G = (Gibbs energy of product) - ( Gibbs energy of reactants)
Reaction given is
H2 + 1/2(O2) >>> H2O
Considering H2O in liquid state, as not given
∆G (H2O) = -237.13 KJ/mol
Gibbs energy for hydrogen and oxygen are taken as zero as per convention
So change in free energy for above reaction is = -237.13 KJ/mol
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