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The action of enzymes is often described as following a two-step mechanism, named after the biochemists...

The action of enzymes is often described as following a two-step mechanism, named after the biochemists Michaelis and Menten, where in the first step the enzyme and the substrate form an intermediate complex, and in the second step the enzyme is released and the product is formed.

Schematically, E + S ⇆ ES (fast) , k1 and k-1 are the rate constants for the direct and reverse reactions respectively.

ES → E + P (slow), k2 is the rate constant for the reaction. where E=enzyme; S=substrate; ES=enzyme-substrate intermediate complex, and P=product.

If an enzymatic reaction follows this mechanism, what rate law is expected for the reaction?

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> thnks

Danniel Georgia Thu, Jan 2, 2025 12:38 AM

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