A typist makes an average of 4 typo errors per page that she types. If the number of errors per each typed page can be modeled according to the Poisson distribution, what is the probability that she will make more than 3 typo errors in the next page? Express your answer in decimals and round to two significant places after the decimal. For example 0.1678 should be entered as 0.17.
X ~ Poisson (
)
Where
= 4 errors per
page.
Poisson probability distribution is
P(X) = e-
*
X /
X!
P(X > 3) = 1 - P( X <= 3)
= 1 - [ P( X = 0) + P (X = 1) + P( X = 2) + P( X = 3) ]
= 1 - [ e-4 + e-4 * 4 + e-4 * 42 / 2 ! + e-4 * 43 / 3! ]
= 0.57
A typist makes an average of 4 typo errors per page that she types. If the...
A typist makes an average of 5 typo errors per page that she types. If the number of errors per each typed page can be modeled according to the Poisson distribution, what is the probability that she will make more than 3 typo errors in the next page?
6. A certain typing agency employs 3 typists. The average number of errors per article is 2.2 when typed by the first typist, 2.7 when typed by the second, and 3.1 when typed by the third. If your article is equally likely to be typed by any of the three typists, approximate the probability that it will have no errors. Again assume that for each typist the number of errors follows a Poisson distribution.
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