IQ scores (as measured by the Stanford-Binet intelligence test) in a certain country are normally distributed with a mean of 85 and a standard deviation of 19. Find the approximate number of people in the country (assuming a total population of 323,000,000) with an IQ higher than 121. (Round your answer to the nearest hundred thousand.)
people
mean = 85, sd = 19

Total people = 3230000000
So, E(x) = 323000000*0.02906364 = 9387555.72
Hence, we expect that 9400000 (rounded to hundred thousand) to have IQ higher than 121.
Please comment if any doubt. Thank you.
IQ scores (as measured by the Stanford-Binet intelligence test) in a certain country are normally distributed...
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