Question

In MIPS

In part 4 you must make an assembly program multiplies a stored value by 26 (start with Multiply.s). Note you CANNOT use the multiply command or a simple looped addition routine, you must write the solution to make use of shifts (both left and/or right) and at most three adds/subs to get the right multiplier of 26. You will print out your total when finished. Name your new file Lastname-Multiply.s Make sure you comment your code so I (and more so you) understand what you are doing

Answer 1

COPY TO CODE:

# Filename: Multiply.s
# Target: MIPS ISA Simulator
# Author:
# Description: Multiply a hardcoded register value by 30 using only shifts and a simple add
# store preloaded data here if needed (not used in this program).
.data
result_text: .asciiz "The value of the multiplication is: "
# Program body
.text
.globl main
main:

# initilization
addi $s0, $0, 5 # initialize $s0 = 5 Use this value to multiple by 30
sll $s1,$s0,5 #it will multiply number by 32 and store in s1
sll $s2,$s0,1 #it will multiply number by 2 and store in s2
#implement your multipliciation scheme
neg $s2,$s2 #set s2 to negative
add $s0,$s1,$s2 #now add both s1 and s2 and store to s0 32*number - 2*number = 30*number

# Print the result
li $v0,1
move $a0,$s0 #print result
syscall
# program exit

SNIPPET: