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A golf ball (m = 21.8 g) is hit by a club that makes an angle...

A golf ball (m = 21.8 g) is hit by a club that makes an angle of 30 ◦ with the horizontal. The ball lands 223 m away on a flat fairway. The acceleration of gravity is 9.8 m/s 2 . If the golf club and ball are in contact for 5.18 ms, what is the average force of impact? Neglect air resistance. Answer in units of N.

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Answer #1

Initial speed = u

horizontal component of initial velocity = u Cos(300)

vertical component of initial velocity = u Sin(300)

Total horizontal distance travelled = s = 223 m

gravitaitional acceleration = g = 9.8 m/s2

mass of the ball = m = 21.8 g = 0.0218 Kg

Let the time of flight be = t

Do comment if you need further clarification.

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