A quality control inspector has drawn a sample of 1919 light bulbs from a recent production lot. If the number of defective bulbs is 11 or more, the lot fails inspection. Suppose 10%10% of the bulbs in the lot are defective. What is the probability that the lot will fail inspection? Round your answer to four decimal places.
X ~ Bin ( n , p)
Where n = 19 , p = 0.10
We have to calculate P(X >= 11) = ?
P(X >= 11) = 1 - P(X <= 10)
= 1 - BINOM.DIST ( number_s , trials, probability_s , cumulative)
= 1 - BINOM.DIST ( 10 , 19 , 0.10 , TRUE)
= 1 - 1
= 0.0000
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