It is given that :
m = 49 kg, D = 50 m, F = 116 N, L = 40 m,
=
50o and M = 80 kg



Jane, whose mass is 49.0 kg, needs to swing across a river filled with man-eating crocodiles...
7.10. Please answer all the
questions and show your work.
Jane, whose mass is 50.0 kg, needs to swing across a river (having width D) filled with person-eating crocodiles to save Tarzan from danger. She must swing into a wind exerting constant horizontal force F vector, on a vine having length L and initially making an angle theta with the vertical (see below figure). Take D = 48.0 m, F vector = 115 N, L = 40.0 m, and theta...
The answer is NOT 20.39 or 0.361. It should be around 7 but I am
not sure how to get there
3. 2.5/5 points Previous Answers SerPSE10 8.C.OP.041. My Notes Ask Your Teacher In order for Jane to return to base camp, she needs to swing across a river of width D that is filled with alligators. She must swing into a wind exerting constant horizontal force F, on a vine having length L and initially making an angle with...
An online video daredevil is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The daredevil's mass is 82.0 kg, the vine is 12.0 m long, and the speed of the daredevil at the bottom of the swing has been determined to be 7.80 m/s. What is the minimum tension force (in N) the vine must be able to support...
An online video daredevil is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The daredevil's mass is 82.0 kg, the vine is 11.0 m long, and the speed of the daredevil at the bottom of the swing has been determined to be 8.60 m/s. What is the minimum tension force (in N) the vine must be able to support...
An online video daredevil is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The daredevil's mass is 88.0 kg, the vine is 12.0 m long, and the speed of the daredevil at the bottom of the swing has been determined to be 7.20 m/s. What is the minimum tension force (in N) the vine must be able to support...
A movie stunt performer is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The stunt performer's mass is 82.0 kg, the vine is 10.5 m long, and the speed of the stunt performer at the bottom of the swing has been determined to be 7.60 m/s. What is the minimum tension force (in N) the vine must be able...
An online video daredevil is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The daredevil's mass is 88.0 kg, the vine is 10.5 m long, and the speed of the daredevil at the bottom of the swing has been determined to be 7.20 m/s. What is the minimum tension force (in N) the vine must be able to support...
A man with a mass 80 kg tries to cross a river by swinging from a vine. The vine is 11.5 m long and his speed at the bottom is 8.25 m/s. What is the kinetic energy at the bottom of the swing? What is the tension at the bottom of the swing? If the total energy is equal to the KE at the bottom, what angle does the vine make with the vertical when the man first starts swinging...
-/3 POINTS SERCP11 7.4.OP.018. MY NOTES ASK YOUR TEACHER An online video daredevil is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough strength so that it doesn't break while swinging. The daredevil's mass is 88.0 kg, the vine is 11.5 m long, and the speed of the daredevil at the bottom of the swing has been determined to be 8.40 m/s. What is the minimum tension force...
I need help with the last three questions
the Loop A mass m -82 kg slides on a frictionless track that has a drop, followed by a loop-the-loop with radius R 7.8 m and finally a flat straight section at the same height as the center of the loop (17.8 m off the ground). Since the mass would not make it around the loop if released from the height of the top of the loop (do you know why?) it...