Calculate the pH at 25°Cof a 0.36Msolution of pyridinium chloride C5H5NHCl. Note that pyridine C5H5N is a weak base with a pKb of 8.77.Round your answer to 1 decimal place.
concentration of C5H5NHCl = 0.36 M
pKb = 8.77
this is the salt of strong acid and weak base. so pH < 7
pH = 7 - 1/2 (pKb + log C)
= 7 - 1/2 (8.77 + log 0.36)
pH = 2.8
Calculate the pH at 25°Cof a 0.36Msolution of pyridinium chloride C5H5NHCl. Note that pyridine C5H5N is...
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