CREATE TABLE Gender (
gender CHAR(1),
description VARCHAR(10),
PRIMARY KEY (gender)
);
CREATE TABLE People (
ID INT,
name VARCHAR(50),
gender CHAR(1),
height FLOAT,
PRIMARY KEY (ID),
FOREIGN KEY (gender) REFERENCES Gender (gender)
);
CREATE TABLE Sports (
ID INT,
name VARCHAR(50),
record FLOAT,
PRIMARY KEY (ID),
UNIQUE (name)
);
CREATE TABLE Competitions (
ID INT,
place VARCHAR(50),
held DATE,
PRIMARY KEY (ID)
);
CREATE TABLE Results (
peopleID INT NOT NULL,
competitionID INT NOT NULL,
sportID INT NOT NULL,
result FLOAT,
PRIMARY KEY (peopleID, competitionID, sportID),
FOREIGN KEY (peopleID) REFERENCES People (ID),
FOREIGN KEY (competitionID) REFERENCES Competitions (ID),
FOREIGN KEY (sportID) REFERENCES Sports (ID)
);
CREATE TABLE Accounts (
peopleID int PRIMARY KEY,
sum varchar(255),
last_updated date,
FOREIGN KEY (peopleID) REFERENCES People (id)
);
Question:
Solution have to be in SQL.
Create a trigger CreateAccountForAthlete that when a new athlete
is created, this trigger should
create an account for the athlete. The initial amount on the
account should be 0 and don’t forget
to update the column last_updated.
TRIGGER:
create trigger CreateAccountForAthlete
after INSERT
on
People
for each row
Insert into Accounts (peopleID, sum, last_updated) values ((select max(ID) from people), 0, select CURDATE());
CREATE TABLE Gender ( gender CHAR(1), description VARCHAR(10), PRIMARY KEY (gender) ); CREATE TABLE People (...
CREATE TABLE person ( pid INTEGER NOT NULL ,pname VARCHAR(30) NOT NULL ,PRIMARY KEY (pid) ); CREATE TABLE organization ( oid INTEGER NOT NULL ,oname VARCHAR(30) NOT NULL ,PRIMARY KEY (oid) ); CREATE TABLE venue ( vid INTEGER NOT NULL ,area CHAR(1) NOT NULL ,capacity INTEGER NOT NULL ,PRIMARY KEY (vid) ); CREATE TABLE calendar ( vid INTEGER NOT NULL ,date DATE NOT NULL ,price NUMERIC(6,2) NOT NULL ,PRIMARY KEY(vid,date) ,FOREIGN KEY(vid) REFERENCES venue(vid) ); CREATE TABLE event ( eid...
CREATE TABLE Users ( userId varchar (30) NOT NULL, pass varchar (30), fname varchar (50), lname varchar (50), email varchar (50), gender char(1), age integer, banned boolean, PRIMARY KEY (userId), UNIQUE(email)) CREATE TABLE FavSellers ( userId varchar (30), sellerId varchar (30), PRIMARY KEY (userId, sellerId), FOREIGN KEY(userId) references Users, FOREIGN KEY(sellerId) references Users(userId)) CREATE TABLE Items ( itemId integer, title varchar (50), ...
create table candidate ( cand_id varchar(12) primary key, -- cand_id name varchar(40) -- cand_nm ); create table contributor ( contbr_id integer primary key, name varchar(40), -- contbr_nm city varchar(40), -- contbr_city state varchar(40), -- contbr_st zip varchar(20), -- contbr_zip employer varchar(60), -- contbr_employer occupation varchar(40) -- contbr_occupation ); create table contribution ( contb_id integer primary key, cand_id varchar(12), --...
The following SQL DDL script creates a database for a social network application. create table userProfile( id char(10) primary key, firstName varchar(20), lastName varchar(20), dob date, email varchar(30) ); create table foaf( userid char(10), friendID char(10), timeEstablished date, constraint pk primary key(userid, friendID), constraint fk1 foreign key(userid) references userProfile(id), constraint fk2 foreign key(friendID) references userProfile(id) ); create table activity( actID char(20) primary key, topic varchar(20), description varchar(100), location varchar(20), ActivityDate date, hostUser char(10), foreign key(hostUser) references userProfile(id) ); create table...
Use an INSERT INTO statement with a subquery containing a SQL string function to create user names for the volunteers based on their legal names and insert them into the table. +----------------------+ | Tables_in_volunteers | +----------------------+ | address | | email | | funds | | hours | | person | | phone | | users | +----------------------+ users legal names are in the address table user table is : CREATE TABLE USERS(volunteer_id INT NOT NULL, username VARCHAR(50), PRIMARY KEY...
Using SQL and the following info Question 3: Find the people who do not have Viper Certification but are still assigned to Viper class ship Find the fname, lname, and ship_instance_id for all people who do not have Viper certification but are assigned to at least one instance of a Viper class ship (this includes all variants of Viper class ships). Return a row for every ship/person combination. Order your results by fname in ascending order. Use the BSG database...
Using SQL and the following info Question 3: Find the people who do not have Viper Certification but are still assigned to Viper class ship Find the fname, lname, and ship_instance_id for all people who do not have Viper certification but are assigned to at least one instance of a Viper class ship (this includes all variants of Viper class ships). Return a row for every ship/person combination. Order your results by fname in ascending order. Use the BSG database...
CREATE TABLE Bill( bill_id char(15) PRIMARY KEY, bill_name VARCHAR(150) NOT NULL, dateOfVoteCommittee date, dateOfVote date, isPassed tinyint(1) CHECK (isPassed IN (0,1)), date_signed date, isVeto tinyint(1) CHECK (isVeto IN (0,1)), dateOfVote_override date, proposed_person_id INT, committee_id INT, foreign key(proposed_person_id) REFERENCES Congressman(person_id), foreign key(committee_id) REFERENCES Committee(committee_id) ); INSERT INTO Bill (bill_id, bill_name, dateOfVote, isPassed, date_signed, isVeto, dateOfVote_override, proposed_person_id, commitee_id) VALUES(1,'SB2 Florida Statutes',DATE'2019-03-27',1,DATE'2019-03-27',0,23,); *I am getting this error - mysql Mysql doesn't like the date entries in the insert statement. Schema above for reference.
Help In Database: Next comes the data entry: Make up data for your database, or find real data. You can enter the data with INSERT statements, but it is much easier to use PhpAdmin. It has a form where you can type the data directly. Alternatively, you can use PhpAdmin to import CSV data (comma-separated values), which you can export from Excel. Include at least 3 rows in each of the entity relations, and as many rows as you need...
-- Schema definition
create table Customer (
cid smallint not null,
name varchar(20),
city varchar(15),
constraint customer_pk
primary key (cid)
);
create table Club (
club varchar(15) not null,
desc varchar(50),
constraint club_pk
primary key
(club)
);
create table Member (
club varchar(15) not null,
cid
smallint not null,
constraint member_pk
primary key (club,
cid),
constraint mem_fk_club
foreign key (club)
references Club,
constraint mem_fk_cust...