1) Please calculate the number of moles that are in 10.0 mL of water (H2O).
2) please calculate the mixed volume (Vmix) when 0.300 mol of ethanol and 0.300 mol of water are mixed.
a) 74.3mL
b)22.3mL
c) 22.3mL
d) 37.2mL
3) Please calculate the mole fraction of ethanol and the mole fraction of water when
0.300 mol of ethanol and 0.200 mol of water are mixed.
mole fraction of ethanol = 0.150 mole fraction of water = 0.150 |
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mole fraction of ethanol = 0.600 mole fraction of water = 0.400 |
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mole fraction of ethanol = 0.500 mole fraction of water = 0.500 |
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mole fraction of ethanol = 0.300 mole fraction of water = 0.300 |
1) The moles of water are calculated:
n water = 10 mL * (1 g / 1 mL) * (1 mol / 18 g) = 0.56 mol
2) The volume of water and ethanol and the mixture are calculated:
V water = 0.3 mol water * (18 g / 1 mol) * (1 mL / 1 g) = 5.2 mL
V ethanol = 0.3 mol * (46.07 g / 1 mol) * (1 mL / 0.789 g) = 17.1 mL
V mix = 5.2 + 17.1 = 22.3 mL
3) The molar fraction is calculated:
X water = n water / n total = 0.2 / 0.5 = 0.400
X Ethanol = 1 - 0.4 = 0.600
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