For a standing wave in a closed-closed tube, the mode number is the same as:
a. the number of displacement antinodes for each standing wave that meets the boundary conditions.
b. the ratio L/λ
c. the number of displacement nodes for each standing wave that meets the boundary conditions.
d. the ratio 2L/λ
e. the number of boundary conditions.
f. the total number of modes.
g. the ratio of L/(2λ)
here in this condition possible ways are shown..
this acts just like stretched string
possible options are a and dt
in these types of problem draw possible type and proceed , thank you
For a standing wave in a closed-closed tube, the mode number is the same as: a....
Pre-Lab for LAB#11 Waves in air may be represented by oscillations of air molecules or of air pressure. When representing standing waves in air, displacement nodes correspond to pressure antinodes (places of greatest pressure variation), and displacement antinodes correspond to pressure nodes (places of least pressure variation). Problem Consider a pipe that is closed at one end. Sketch the standing wave pattern in each of the following situations to show the regions of greatest and least air pressure variations (pressure...
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A tube, open at the left end and closed at the right, has standing-wave patterns at frequencies of 198 Hz and 330 Hz. The speed of sound in air is 343 m/s. The lowest two harmonics (normal modes) that these two standing waves could be are m = and The frequency of the fundamental (m = 1) is Hz. The wavelength of the fundamental mode is m. The tube is m long
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