let the velocity of car be 'vc' and approaching the source, and v is the speed of sound in air
frequency as heard by the car, f' = f*((v+vc)/ v) = 2.1*1010*(1+(vc/343))
frequency as heard back by the source,(now we'll consider the car to be the source with frequency f')
f'' = f'*(v/(v-vc))
putting the respective values, and given that f'' = f+1030
f+ 1030 = f*((v+vc)/ v)*(v/(v-vc))
2.1*1010 + 1030 = 2.1*1010*(1+(vc/343))*(343/(343-vc))
1 + (1030/(2.1*1010)) = ((343 + vc)/(343-vc))
solving for vc we get
vc = 8.411*10-6
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