Question

A friend of mine likes to eat peanut M&M’s. Each morning he randomly selects a number of Peanut M&M’s between 1 and 12 to eat during the day from a bag which originally contained 100 Peanut M&M’s.(Hint: Looks like a randi(12) might be used here!). The question is on what day will my friend have to open a new bag of M&M’s for his daily habit. That means that if on day t the last M&Ms are eaten, then on day t+1 he has to start a new bag. By the way, on the last day if the random integer is equal to or greater than the number of M&M’s left, then he eats all that are left.

Notes:

1. (1) For our previous problems, we have ONLY used for/end loops. That was because we knew EXACTLY how many times to loop through the code. In this problem, you are to find the number of days (aka: loops), so a while-end is used.

2. (2) REMEMBER that for a for-end loop, the loop index variable is incremented for you. In a while loop, YOU must increment the loop index variable.

3. (3) So MOST days you will have the number of Peanut M&M’s left at the beginning of the day as P(t)and at the end of the day as: P(t+1)=P(t)–randi(12)

4. (4) The way to deal with the last day is that when P(t+1)<=0 set P(t+1)=0.

5. (5) Don’t forget to initialize your “t”.

Answer 1

Hi,

The problem has been solved. While loop has been used to solve the problem. Everyday a random function "rand(12)" will give the value from 0-12 days. A screenshot has been attached for better understanding.

Screenshot:

Code:

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import java.util.*;
class Peanut{

   public static void main(String[] args){

       int total=100;

       Random random = new Random();
      
       int t=1;

       while(total>0){
           int rand= random.nextInt(12);
           total= total-rand;
           t++;
           //System.out.println(total+" -> "+t);
       }

       System.out.println(t+" day will my friend have to open a new bag of M&M’s for his daily habit");

   }

}

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The problem has been resolved, I hope you will like the solution. If you have any question or query regarding this problem or other, please comment below and give the positive rating.

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