A 25-hp, 208-V, 60-Hz, two-pole, Y-connected induction motor operates at slip of 5% at rated conditions....
A 25-hp, 208-V, 60-Hz, two-pole, Y-connected induction motor
operates at slip of 5% at rated conditions. The motor parameters
are given in ohms per phase as follows:
??=0.3 ??=0.4 ??=0.1 ??=0.4 ??=25.0
Assume core loss of 150 W and rotational loss of 225 W,
Find Stator Current, Electromechanical torque, Power out, Efficiency, Power Factor and PowerFlow Diagram. Use the exact model circuit.
Homework Answers
Please provide rating as it keeps us
motivated to help you more.Add Answer to:
A 25-hp, 208-V, 60-Hz, two-pole, Y-connected induction motor
operates at slip of 5% at rated conditions....
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the ...
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters in Ω/phase referred to the stator: R,-0.220, Xi = 0.430, X,-15.0, R2 0.130 and X2-0.430. Mechanical and core losses amount to 300 W and 200 W respectively for rated voltage. (a) The motor is fed with a 60 Hz, 208 V voltage. It runs with a slip of 4.5 %. Find the speed, shaft torque and power, efficiency and power...
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor
A 3-phase, 208 V, 60 Hz, 30 hp, four-pole induction motor has the following equivalent circuit parameters. R1 = 0.2 Ω, , , Xm = 12Ω.The rotational loss is 500 W. For a slip of 5%, calculate (a) The motor speed in rpm and radians per sec (b) The current drawn by the motor from the power supply (c) The stator cu-loss (d) The air gap power (e) The rotor cu-loss (f) The shaft power (g)The developed torque and the shaft torque (h) The efficiency of the motor Use...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
5. A 208-V four-pole 60-Hz Y-connected wound-rotor induction motor is rated at 30 hp. Its equivalent...
5. A 208-V four-pole 60-Hz Y-connected wound-rotor induction motor is rated at 30 hp. Its equivalent circuit components are R=0.100 Ry=0.070. X - 10.00 R = 250 X; -0.2100 X=0.21002 Praw=500 W P =0.5% of input at full load For a slip of 0.05, find (a) The line current (b) The induced voltage in the rotor (c) The stator power factor (d) The rotor power factor (e) The rotor frequency (f) The stator copper losses (g) The core loss (h)...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected induction motor draws 25...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected
induction motor draws 25 A at a power factor of 0.9 lagging. Core
loss is 900 W, stator copper loss is 1100W, friction and winding
losses are 300 W, and stray loss is neglected. The machine shaft
rotates at 1738 rpm. Calculate the air gap power and output load
torque
- [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
core (b) A 460-V 60-Hz four-pole Y-connected induction motor is rated at 25 hp. The equivalent...
(b) A 460-V 60-Hz four-pole Y-connected induction motor is ratedat \(25 \mathrm{hp}\). The equivalent circuit parameters are$$ \begin{array}{ll} R_{1}=0.15 \Omega & R_{2}=0.154 \Omega \quad X_{M}=20 \Omega \\ X_{1}=0.852 \Omega & X_{2}=1.066 \Omega \\ P_{\mathrm{F} \& \mathrm{~W}}=400 \mathrm{~W} & P_{\text {misc }}=150 \mathrm{~W} \end{array} $$\(P_{\text {core }}=400 \mathrm{~W}\) (lumped with rotational losses)[14 points]For a slip of \(0.02\), find(1) The line current \(I_{L}\). [3 points](2) The stator power factor. [1 point](3) The rotor power factor. [1 point](4) The rotor frequency. [1 point](5)...
A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with...
A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A. 2200 W, 15 Hz 13.5 V, 64 A de test: a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
2. A 208V, two pole, 60 Hz, y connected wound rotor induction motor is rated at...
2. A 208V, two pole, 60 Hz, y connected wound rotor induction motor is rated at 15hp. Its equivalent circuit parameters are R:-0.200, R:-0.120, X.-X-0.410, X-150. The rotational losses are 430W. The motor drives a mechanical load with a slip of 5 percent. By using simplified equivalent circuit calculate; (30 pts) a) The motor speed in revolutions per minute and radians per second. b) The line current c) The stator copper losses. d) The air gap power. e) The power...
Name: Student ID: A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in...
Name: Student ID: A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A, 2200 W, 15 Hz dc test: 13.5 V, 64 A a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
A three phase, 60 Hz induction motor rated at 440 V and 40 hp drives a...
A three phase, 60 Hz induction motor rated at 440 V and 40 hp drives a load at 1710 rpm. The induction motor has the following impedances referred to the stator in /phase: R,=0.1512, X,=0.7512; R2=1.222,X=0.7522; X=25 12 . The core loss is 450 W and friction and windage loss is 250 W. Calculate the following 1. line current and power factor 2. Real and reactive input power 3. Air-gap power 4. Mechanical power and torque developed 5. shaft horse...
1. A 15 hp, 4 pole, 208 V, 60 Hz, Y-connected, three-phase squirrel cage induction motor has the following parameters in Ω/phase referred to the stator: R,-0.220, Xi = 0.430, X,-15.0, R2 0.130 and X2-0.430. Mechanical and core losses amount to 300 W and 200 W respectively for rated voltage. (a) The motor is fed with a 60 Hz, 208 V voltage. It runs with a slip of 4.5 %. Find the speed, shaft torque and power, efficiency and power...
. A 460-V 460-V, 25-hp, 60-Hz, six-pole, Y-connected induction motor has the following impedanc ohms per phase referred to the stator circuit. Ri= 0.212 R2 = 0.282 X1 = 1.055 12 X2 = 1.055 22 XM = 33.9 W The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped with the rotational losses. For a rotor slip of 4% at the rated voltage and rated frequency, a) The input power b) Peony...
5. A 208-V four-pole 60-Hz Y-connected wound-rotor induction motor is rated at 30 hp. Its equivalent circuit components are R=0.100 Ry=0.070. X - 10.00 R = 250 X; -0.2100 X=0.21002 Praw=500 W P =0.5% of input at full load For a slip of 0.05, find (a) The line current (b) The induced voltage in the rotor (c) The stator power factor (d) The rotor power factor (e) The rotor frequency (f) The stator copper losses (g) The core loss (h)...
A 4 phase, 460 V, 60 Hz, 26.8 hp, 4 pole, Y-connected
induction motor draws 25 A at a power factor of 0.9 lagging. Core
loss is 900 W, stator copper loss is 1100W, friction and winding
losses are 300 W, and stray loss is neglected. The machine shaft
rotates at 1738 rpm. Calculate the air gap power and output load
torque
- [Induction Motor - 15 points) A three-phase, 460 V, 60 Hz, 26.8 hp, 4-pole, Y-connected induction motor...
(b) A 460-V 60-Hz four-pole Y-connected induction motor is ratedat \(25 \mathrm{hp}\). The equivalent circuit parameters are$$ \begin{array}{ll} R_{1}=0.15 \Omega & R_{2}=0.154 \Omega \quad X_{M}=20 \Omega \\ X_{1}=0.852 \Omega & X_{2}=1.066 \Omega \\ P_{\mathrm{F} \& \mathrm{~W}}=400 \mathrm{~W} & P_{\text {misc }}=150 \mathrm{~W} \end{array} $$\(P_{\text {core }}=400 \mathrm{~W}\) (lumped with rotational losses)[14 points]For a slip of \(0.02\), find(1) The line current \(I_{L}\). [3 points](2) The stator power factor. [1 point](3) The rotor power factor. [1 point](4) The rotor frequency. [1 point](5)...
A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A. 2200 W, 15 Hz 13.5 V, 64 A de test: a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
2. A 208V, two pole, 60 Hz, y connected wound rotor induction motor is rated at 15hp. Its equivalent circuit parameters are R:-0.200, R:-0.120, X.-X-0.410, X-150. The rotational losses are 430W. The motor drives a mechanical load with a slip of 5 percent. By using simplified equivalent circuit calculate; (30 pts) a) The motor speed in revolutions per minute and radians per second. b) The line current c) The stator copper losses. d) The air gap power. e) The power...
Name: Student ID: A 208-V, six-pole, Y-connected, 25-hp design class B induction motor is tested in the laboratory, with the following results: No load: 208 V, 24.0 A, 1400 W, 60 Hz Locked rotor: 24.6 V, 64.5 A, 2200 W, 15 Hz dc test: 13.5 V, 64 A a) Find the parameters of the induction motor equivalent circuit. b) Calculate the stator current if the slip is 0.02.
A three phase, 60 Hz induction motor rated at 440 V and 40 hp drives a load at 1710 rpm. The induction motor has the following impedances referred to the stator in /phase: R,=0.1512, X,=0.7512; R2=1.222,X=0.7522; X=25 12 . The core loss is 450 W and friction and windage loss is 250 W. Calculate the following 1. line current and power factor 2. Real and reactive input power 3. Air-gap power 4. Mechanical power and torque developed 5. shaft horse...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago