Question

Question 4 (1 point)

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 22 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 22 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is -3.83 strokes and the standard deviation of the differences is 6.515 strokes. The owner uses this information to calculate the 95% confidence paired t-interval of (-6.719, -0.941). Which statement is the correct interpretation of this interval?

Question 4 options:

	1) The proportion of all golfers that had a difference in scores between the two courses is 95%.
	2) We are 95% confident that the average difference in the scores of the golfers sampled is between -6.719 and -0.941.
	3) We are 95% confident that the average difference in scores between the two courses for all golfers is between -6.719 and -0.941.
	4) We are 95% confident that the difference between the average score on the owner's golf course and the average score on the friend's golf course is between -6.719 and -0.941.
	5) We are certain the average difference in scores between the two courses for all golfers is between -6.719 and -0.941.

Answer 1

Here the calculated confidence interval is (-6.719, -0.941)

We are 95% confident that the difference between the average score on the owner's golf course and the average score on the friend's golf course is between -6.719 and -0.941.

option (4)