ten measurements of a given length that has mean value x= 12.2 and sample standard deviation...
ten measurements of a given length that has mean value x= 12.2 and sample standard deviation of Sx= 1.41 , write the is the precision intreval for 95% probability using Student's t distribution ? ( 5 points ) xi = xmean ± ux (p%), how much is the random uncertainty x true = xmean ± uxmean (p%),
Homework Answers
Sol: The values provided in the question are as follows:
x= 12.2, Sx= 1.41. n= 10....(ten measurements)
To find - x true = mean +- uxmean
we get value of t*=2.262 from table of probability and df
ux is 1.0086 ......(answer)
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ten measurements of a given length that has mean value x= 12.2
and sample standard deviation...
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