Scores on an English test are normally distributed with a mean of 37.6 and a standard deviation of 7.6. Find the score that separates the top 59% from the bottom 41%
answers choices:
35.9
39.3
42.1
33.1
solution
Using standard normal table,
P(Z > z) = 59%
= 1 - P(Z < z) = 0.59
= P(Z < z ) = 1 - 0.59
= P(Z < z ) = 0.41
= P(Z < -0.23 ) = 0. 41
z = -0.23 (using standard normal (Z) table )
Using z-score formula
x = z *
+
x= -0.23 *7.6+37.6
x= 35.9
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