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Constants A 510-turn solenoid is 19 cm long. The current in it is 37 A ....

Constants A 510-turn solenoid is 19 cm long. The current in it is 37 A . A straight wire cuts through the center of the solenoid, along a 5.0-cm diameter. This wire carries a 26-A current downward (and is connected by other wires that don't concern us). What is the force on this wire assuming the solenoid's field points due east?

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Answer #1

net force is given by the following expression

F = uo N i (i' L) /l

F = 4* 3.14* 10^-7* 510* 37* 26* 0.05 / 0.19

F = 0.162 N

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