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A proton is placed in an electric field of intensity 0.0900 N/C. What are the magnitude...

A proton is placed in an electric field of intensity 0.0900 N/C. What are the magnitude and direction of the acceleration of the proton due to this field? (e = 1.60 × 10-19 C, mproton = 1.67 × 10-27 kg)

A. 8.62 ×106 m/s2 opposite to the electric field

B. 9.39 × 10-10 m/s2 opposite to the electric field

C. 8.62 × 106 m/s2  in the direction of the electric field

D. 9.39 × 104 m/s2 opposite to the electric field

E. 8.62 × 108 m/s2 in the direction of the electric field

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