Question

Terrain analysis. Suppose that a terrain is represented by a two-dimensional grid of elevation values (in meters). A peak is a grid point whose four neighboring cells (left, right, up, and down) have strictly lower elevation values. Compose a program peaks.py that reads a terrain from standard input and then computes and writes the number of peaks in the terrain. HAVE TO BE IN PYTHON PLEASE. using stdarray.

Answer 1

below is the code for Terrain analysis. max function will give max of the passed arguments i had used max with 4 arguments max.

_________________________PYTHON 3.X code___________________________

n = int(input())   _{# for takin length of 2D array.}
m = int(input())    _{# for takin length of 2D array.}
arr= [] _{# for makin array itself}
count=0 _{# count of peaks}
for i in range(n): _{# loop for takin inputs}
   arr.append(list(map(int,input().split()))) _{# takin all space saprated input and append list of integers in arr.}

for i in range(n): _{# loop for travesing 2D array}
   for j in range(m): _{# loop for traversing i and j.}
      
       center = arr[i][j] _{# definition of cell}   
       if i==0:    _{# check if i == 0 first row.}
           if j == 0: _{# first element check}
               if center > max(arr[i+1][j],arr[i][j+1]): _{#checking for DOWN and RIGHT cell only.}
                  count+=1
           elif j == m-1:   _{# last element of first row.}
               if center > max(arr[i+1][j],arr[i][j-1]): _{#checking for DOWN and LEFT cell only.}
                   count+=1
           else:
               if center > max(arr[i+1][j],arr[i][j-1],arr[i][j+1]):   _{#checking for DOWN RIGHT and LEFT cells.}
                   count+=1
       elif j == 0:    _{# for first column checking.}
           if i == n-1: _{# last cell of first column.}
               if center > max(arr[i-1][j],arr[i][j+1]): _{#checking for UP and RIGHT cell only.}
                   count+=1
           else:   
               if center > max(arr[i-1][j],arr[i+1][j],arr[i][j+1]): _{#checking for UP DOWN and RIGHT cells.}
                count+=1
      elif i == n-1: _{#checking cells of last row.}
       if j == m-1: _{#checkin last row last element j = m-1.}
              if center > max(arr[i-1][j],arr[i][j-1]): _{#checking for UP and LEFT cell only.}
                   count+=1
           else :
               if center > max(arr[i-1][j],arr[i][j+1],arr[i][j-1]): _{#checking for UP RIGHT and LEFT cells..}
                  count+=1
      elif j == m-1: _{# checking last column. first and last elements are checked in above conditions we will only check middle elements}
           if center > max(arr[i-1][j],arr[i][j-1],arr[i+1][j]): _{#checking for UP DOWN and LEFT cells..}
               count+=1
    else : _{#for all the cells which is not on the edge of the terrain.}
           if center > max(arr[i-1][j],arr[i][j+1],arr[i][j-1],arr[i+1][j]): _{#checking for UP DOWN RIGHT and LEFT cells..}
               count+=1
          
print("the number of peaks in the terrain = " ,count)   _{#output at console}   

___________________INPUT Snippet _____________________________

circled one are the peaks. count is 8 in total.

  

__________________________OUTPUT Snippet________________________________________