2 HI(g) <==> H2(g) + I2(g) the value of Kc = 0.0184
Calculate the value of Kc for this second reaction below:
6 HI(g) <==> 3 H2(g) + 3 I2(g)
The equilibrium constant always has the same value (provided you do not change the temperature).
The equilibrium constant irrespective of the amounts of HI, H2 and I2 you started with.
It is also unaffected by a change in concentrations or whether or not you are using a catalyst.
So, the value for the second reaction is also = 0.0184
2 HI(g) <==> H2(g) + I2(g) the value of Kc = 0.0184 Calculate the value of...
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