Roy must elect 3 courses from among 5 courses in group I and 4 courses in group II. If he must take at least 1 of his 3 electives from each group, how many choices does he have? (Hint: First find how many choices he has if he elects only 1 course from group I. Then find how many choices he has if he elects 2 courses from group I. Since he must do one or the other of these, the final answer is the sum of the two answers.)
1)
total number of choices =9C3 =84
number of ways so that no course from group 1 or group 2 =5C3+4C3 =10+4 =14
hence number of choices such that at least 1 of his 3 electives from each group =84-14 =70
Roy must elect 3 courses from among 5 courses in group I and 4 courses in...
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Question number 9
player A ends Up match, where the match ut r is (b) How many possible outcomes for I up with 4 points and B ends up with 3 points? (c) Now assume that they are playing a best-of when either player has 4 points or when 7 games hav ti For example, if after 6 games the score is 4 to 2 in favor of A, then A wins th s fitst are there, such that the...
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can someone please explain this to me ?
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