Calculate the heat released when 135 grams of ethanol C2H5OH, burns. The heat of combustion of...

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Calculate the heat released when 135 grams of ethanol C2H5OH, burns. The heat of combustion of ethanol is 1233 kJ/mol.

Molar mass of ethanol C2H5OH = 46.07 g/mol C2H5OH(g) + 3 O2(g) → 2 CO2 (g) + 3 H2O(l) LaTeX: \DeltaΔH = -1233 kJ/mol

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Answer 1

Answer #1

Combustion of 1 mole of C2H5OH(g) gives 1233 kJ of heat.
Molar mass of ethanol = 46.07 g/mol
Mass of ethanol burns = 135 g
Moles of ethanol in a given mass= (135 g)/(46.07 g/mol) = 2.93 mol
Combustion of 2.93 mol of Ethanol will give (2.93 mol)(1233 kJ/mol) = 3612.69 JJ
The Heat released when 135 grams of ethanol (C2H5OH) = 3612.69 kJ

Answer 2

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