A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8...
A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The acceleration due to gravity acting on this pendulum is given by
Group of answer choices
a. 9.8 m/s2
b. 27.4 m/s2
c. 19.72 m/s2
d. 4.9 m/s2
Homework Answers
Time period = Total time/No of oscillations
Use formula 
Square both sides
ANSWER: Option c. 19.72m/s2
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A simple pendulum of
length 2 meters takes a time of 16 seconds to
finish 8...
A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8...
A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The acceleration due to gravity acting on this pendulum is given by A)19.72 m/s2 B)27.4 m/s2 C)9.8 m/s2 D)4.9 m/s2
D Question 12 10 pts A simple pendulum of length 2 meters takes a time of...
D Question 12 10 pts A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The accelerat due to gravity acting on this pendulum is given by 9.8 m/s2 19.72 m/s2 4.9 m/s2 O 27.4m/s2 No new data to save. Last checked at 10:37am Submit Quiz MacBook Air 20. 299..
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(1 point) Suppose a pendulum of length L meters makes an angle of θ radians with the vertical, as n the figure t can be...
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TUDIEM 14 Geoff counts the number of oscillations of a simple pendulum at a location where...
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(a) What is the length of a simple pendulum that oscillates with a period of 2.6...
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D Question 12 10 pts A simple pendulum of length 2 meters takes a time of 16 seconds to finish 8 oscillations. The accelerat due to gravity acting on this pendulum is given by 9.8 m/s2 19.72 m/s2 4.9 m/s2 O 27.4m/s2 No new data to save. Last checked at 10:37am Submit Quiz MacBook Air 20. 299..
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TUDIEM 14 Geoff counts the number of oscillations of a simple pendulum at a location where the acceleration due to gravity is 9.80 m/s, and finds that it takes 28.0 s for 17 complete cycles. 1) Calculate the length of the pendulum. (Express your answer to three significant figures.) m Submit
(10 points) Suppose a pendulum with length L (meters) has angle (radians) from the vertical. It can be shown that e as a function of time satisfies the differential equation: de 8 + -sin 0 = 0 dt2 L where g = 9.8 m/sec/sec is the acceleration due to gravity. For small values of we can use the approximation sin(0) - 0, and with that substitution, the differential equation becomes linear. A. Determine the equation of motion of a pendulum...
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