Hydrogen cyanide can be prepared by reacting of methane, CH4, with ammonia by the following reaction.
CH4(g) + NH3(g) →HCN(g) +3H2(g)
What is the heat of reaction at constant pressure? Express your answer in kJ
Useful information:
N2(g) +3H2(g) → 2NH3(g); ΔH = -91.8 kJ
C(graphite) +2H2(g) → CH4(g); ΔH = -74.9 kJ
H2(g) +2C(graphite) +N2(g) → 2HCN(g); ΔH = 270.3 kJ
Lets number the reaction as 0, 1, 2, 3 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 0 = -0.5 * (reaction 1) -1 * (reaction 2) +0.5 * (reaction 3)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = -0.5 * ΔHo rxn(reaction 1) -1 * ΔHo rxn(reaction 2) +0.5 * ΔHo rxn(reaction 3)
= -0.5 * (-91.8) -1 * (-74.9) +0.5 * (270.3)
= 255.95 KJ
Answer: 255.95 KJ
Hydrogen cyanide can be prepared by reacting of methane, CH4, with ammonia by the following reaction....
Given the following data for heats of reaction
N2(g) + 3H2(g) ---->
2NH3(g) H
= -91.8 kJ
C(graphite) + 2H2(g) ------->
CH4(g)H
= -74.9kJ
H2(g) + 2C(graphite) + N2(g)
--------> 2HCN(g) H
= 270.3 kJ
Calculate
H for the reaction used to make HCN
CH4(g) + NH3(g) --------> HCN(g) +
3H2(g)
What is the enthalpy of the following reaction: CH4(g) + NH3(g) à HCN(g) + 3H2(g) Use the data from the following three reactions: N2(g) + 3H2(g) à 2NH3(g) DrH° = -91.8 kJ C(s) + 2H2(g) à CH4(g) DrH° = -74.9 kJ H2(g) + 2C(s) + N2(g) à 2HCN(g) DrH° = +270.3 kJ 437 kJ 150 kJ 391 kJ 287 kJ 256 kJ
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Want 2CH4 + 2NH3 ----> 2HCN + 6H2 From: N2+3H2 --->2NH3 DeltaH: -91.8KJ 2H2+C--->CH4 DeltaH: -74.9 KJ 2C+H2+N2----> 2HCN DeltaH: 270.3 KJ
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