450.0 g of H 2O is at 54.0 oC. It loses
________ kJ of heat to a cooler environment.
The final temperature is 48.7 oC. The specific heat of
water is 4.184 J/g·C. Watch units.
How many kJ of heat did it lose?
|
8.02 kJ |
||
|
11.5 kJ |
||
|
9.98 kJ |
||
|
14.0 kJ |
||
|
25.2 kJ |
12.60 milliliters of a 1.25 M KOH solution are required to
titrate 20.0 milliliters of a H3PO4 solution.
What is the molarity of the H3PO4
solution?
3KOH + H3PO4 -->
K3PO4 + 3H2O
|
0.513 M |
||
|
2.52 M |
||
|
0.0550 M |
||
|
0.728 M |
||
|
3.04 M |
||
|
0.263 M |
||
|
1.45 M |
||
|
0.817 M |
12.60 milliliters of a 1.25 M KOH solution are required to titrate 20.0 milliliters of a H3PO4 solution. What is the molarity of the H3PO4 solution? 3KOH + H3PO4 --> K3PO4 + 3H2O 0.513 M 2.52 M 0.0550 M 0.728 M 3.04 M 0.263 M 1.45 M 0.817 M Refer to this equation: 3SCl2 + 4NaF --> SF4 + S2Cl2 + 4NaCl 64.0 grams SCl2 is reacted with excess NaF and 12.5 grams of SF4 is formed. What is percent...
Refer to this equation: 3SCl2 + 4NaF --> SF4 + S2Cl2 + 4NaCl 64.0 grams SCl2 is reacted with excess NaF and 12.5 grams of SF4 is formed. What is percent yield SF4? Hint: find theoretical yield Hint: percent yield =(actual yield/ theoretical yield) x 100 34.3 % 64.4% 38.0% 27.8 % 55.9 % 92.1% 36.1% 24.6% 12.60 milliliters of a 1.25 M KOH solution are required to titrate 20.0 milliliters of a H3PO4 solution. What is the molarity of...
1)350.0 g of H2O at 30.0 oC is heated to 85.0 oC. How many kJ of heat did it gain from the environment? The specific heat, c, of water is 4.184 J/g·C . 2)A sample of a metal at 90.00°C was added to 200.0 g H 2O at 21.00°C. The temperature rose to 24.50°C. [Specific heat of H 2O is 4.184 J/(g °C). Specific heat of the metal is 0.949 J/(g°C). How many grams of metal was it?\ 3)Use the...