Question

Comp Sci JAVA Log program using controls and loops

1. (1 point) Asks the user to enter an integer base b > 1. (1 point) If the user enter anything less than or equal to 1, you should quit the program. 2. (1 point) Asks the user to enter a positive integer x greater than 0. (2 points) If the user enter anything less than or equal to 0, you should keep asking the user to re-enter a new number until the user enter a valid value. 3. (3 points) Calculate the floor of logb x in the manner indicated above and outputs the result 4. (2 points) Repeats until the user enters b less than or equal to 1 in step 1 The following is an example of a run:

Log base b of x Calculator Please enter a base b (> 1): 10 Please enter a value x (> 0): 123456 Log base 10 of 123456 is 5 Please enter a base b (> 1): 2 Please enter a value x (> 0): 64 Log base 2 of 64 is 6 Please enter a base b (> 1): 10 Please enter a value x (> 0): -123 Invalid value for x...Please enter a value x (> 0): 4567 Log base 10 of 4567 is 3 Please enter a base b (> 1): 0 Goodbye...

Answer 1

If you have any doubts, please give me comment...

import java.util.Scanner;

public class LogProgram{

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Log base b of x Calculator");

while(true){

System.out.print("Please enter a base b (> 1):");

int b = in.nextInt();

if(b==0){

System.out.println("Good Bye...");

break;

}

while(b<0){

System.out.println("Invalid value for b...");

System.out.print("Please enter a base b (> 1):");

b = in.nextInt();

}

System.out.print("Please enter a value x (> 0):");

int x = in.nextInt();

while(x<=0){

System.out.println("Invalid value for x...");

System.out.print("Please enter a value x (> 0):");

x = in.nextInt();

}

int result = (int)(Math.log(x)/Math.log(b));

System.out.println("Log base "+b+" of "+x+" is "+result);

}

}

}