The tread life of tires mounted on light-duty trucks
follows the normal probability distribution with a population mean
of 60,000 miles and a population standard deviation of 4,000 miles.
Suppose you bought a set of four tires, what is the likelihood the
mean tire life of these four tires is between 57,000 and 63,000
miles?
A) 0.4332
B) 0.8664
C) 1.00
D) Very likely
The tread life of tires mounted on light-duty trucks follows the normal probability distribution with a...
Suppose you work at a large tire distribution center. The tires' average tread life has been 50,000 miles with a standard deviation of 5,000 miles At the end of the year, the company can reevaluate their supply contract. There are four supply options for the next contract the current supplier or one of three competitors The current supplier produces tires with an average tread life of 50,000 miles with a standard deviation of 5,000 miles Competitor A claims to produce...
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 3000 miles. What warranty should the company use if they want 96% of the tires to outlast the warranty
Tires are supposed to provide 60,000 miles of service before tread thickness falls below an unsafe limit. If tire service is normally distributed with standard deviation 4,000 miles, then what must be the mean service life so that 95% of all tires will exceed the 60,000-mile requirement ?
Please answer the following question:
Truck tire life is normally distributed with a mean of 60,000 miles and a standard deviation of 4,000 miles. a) What is the probability that a tire will last 72,000 miles or more? b) For a set of four tires, what is the probability that the average tire life is less than 55,000 miles? c) For a set of four tires, what is the probability that the average tire life is between 57,000 and 63,000...
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 2000 miles. What is the probability a certain tire of this brand will last between 55,800 miles and 56,400 miles?
A tire manufacturer believes that the tread life of its snow tires can be described by a normal model with a mean of 32,000 miles and a standard deviation of 2500 miles. Now, assume we took a sample of 26 tires. Find the probability that the tires will last an average of more than 33,500 miles. Round to three decimals.
The tread life of a particular tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 2000 miles. What is the probability that a randomly selected tire of this brand will last longer than 58,000 miles?A.0.7266, B.0.8413, C.0.1587, D.0.2266
A tire company makes tires that have a normal distribution with a mean of 65,000 miles with a standard deviation of 3000 miles prior to needing replacement. Find the probability that a tire lasts no more than 62,500 miles A tire company makes tires that have a normal distribution with a mean of 65,000 miles with a standard deviation of 3000 miles prior to needing replacement. Find the probability that a tire lasts at least 68,500 miles. A tire company...
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000 miles and a standard deviation of 1600 miles. What is the probability a randomly selected tire of this brand will last between 56,640 miles and 57,120 miles? i cant seem to figure this out or even know where to begin!... i would be so,so,so greatful if someone would point me in the right direction and at...
D is incorrect. Please show your work.
19. The life of mixers follows the normal probability distribution with a population mean of 60,000 hours and a population standard deviation of 1750 hours. Suppose you bought a mixer for yourself, your mother, your sister, and your brother. What is the likelihood the mean life of these four mixers is more than 58,000 hours? A. 0.1957 B. 0.9889 C 0.4352 D 0.0121