How many work cycles should be timed to estimate the average
cycle time to within 2 percent of the sample mean with a confidence
of 98.0 percent if a pilot study yielded these times (minutes):
4.1,4.6,5.1, 4.9, 5.9, and 4.4? The standard deviation is .631
minutes per cycle. (Use the "mean time" value to 2 decimal
places and other values to 3 decimal places for intermediate
calculations. Round up your final answer to the next whole
number.)
Number of work cycles
margin of Error = Z* standard deviation / (N)0.5
In the question,
Z for 98% confidence level =2.33
standard deviation=0.631
Margin of error = [(4.1+4.6+5.1+4.9+5.9+4.4)/6]*0.02 =4.83*0.02 =0.097
Margin of Error = Z* standard deviation / (N)0.5
0.097=2.33*0.631/(n)0.5
(N)0.5 =15.157
N=229.73
N=230
Number of work cycle =230
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