Now lets look at momentum in 2 dimensions: a cart with mass m1 is moving with...
Now lets look at momentum in 2 dimensions: a cart with mass m1 is moving with 1 m/s, and its path makes a 30◦ angle with the positive x-axis. It collides with another cart of mass m2 (at rest), and they stick together. How fast, and in what direction, will the two be going after the collision?
Homework Answers
I have explained the concepts in my answer. One thing to note is that the direction of motion of the combined body after collision will be in the same direction as that of m1 before collision. This is because m2 was initially at rest and there is no other factor that will change the direction of motion of m1.
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Now lets look at momentum in 2 dimensions: a cart with mass m1
is moving with...
Assume momentum is conserved in this case. Cart A of unknown mass is moving on a...
Assume momentum is conserved in this case. Cart A of unknown mass is moving on a friction balanced track with a speed 0.422m/s. It then collides with cart B of mass 0.42kg which is at rest, becoming stuck together with a speed 0.24m/s. What is the mass of cart A in (kg) after collision?
8) In a lab demonstration, a cart with mass 0.15 kg that is moving at 0.6...
8) In a lab demonstration, a cart with mass 0.15 kg that is moving at 0.6 m/s collides against a second cart that is at rest previously to the collision. The carts are padded with Velcro so they stick together, moving as a unit after the collision with speed 0.18 m/s. What is the mass of the second cart?
A 5 kg cart moving at a velocity 2 m/s in the +x-direction collides completely inelastically...
A 5 kg cart moving at a velocity 2 m/s in the +x-direction collides completely inelastically (i.e. they stick) with a second cart of mass 1.5 kg which is initially moving at a velocity of 10 m/s in the +y-direction. What is the total initial kinetic energy? J. What is the total x-component of momentum just before the collision? Kg m/s. What is the total y-component of momentum just before the collision? Kg m/s. What is the total x-component of momentum just after...
An atom of mass m1 = m moving in the x direction with speed v1 =...
An atom of mass m1 = m moving in the x direction with speed v1 = v collides elastically with an atom of mass m2 = 4m at rest. After the collision the first atom moves in the y direction. Find the direction of motion of the second atom. _______ ° counterclockwise from the +x-axis Find the speeds of both atoms (in terms of v) after the collision. v'1 =_____ v v'2 =______ v
#1: An atom of mass m1 = m moving in the x direction with speed v1...
#1: An atom of mass m1 = m moving in the x direction with speed v1 = v collides elastically (perfect collision) with an atom of mass m2 = 3m at rest. After the collision, the first atom moves in the y direction. Find the direction of motion of the second atom and the speeds of both atoms (in terms of v) after the collision.
Cart 1, with m1= 5.5 kg, is moving on a frictionless linear air track at an...
Cart 1, with m1= 5.5 kg, is moving on a frictionless linear air track at an initial speed of 1.7 m/s. It undergoes an elastic collision with an initially stationary cart 2, with m2, an unknown mass. After the collision, cart 1 continues in its original direction at 0.6 m/s. 1) The horizontal component of the momentum is conserved for A. cart 1. B. cart 2. C. the system of cart 1 and cart 2. D. Momentum is not conserved...
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves...
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves toward second identical air cart that is at rest. When the carts collide, they stick together and move as one a) Using the conservation of linear momentum, calculate the velocity ve when the carts stick together (this is also the velocity of the center of mass after collision). b) Calculate the kinetic energy before and after collision. Is the collision elastic Without any calculation,...
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a...
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a...
A block of mass m1 = 1.10 kg moving at v1 = 1.20 m/s undergoes a completely inelastic collision with a stationary block of mass m2 = 0.900 kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.40 kg , which is initially at rest. The three blocks then move, stuck together, with speed v3. Assume that the blocks slide without...
A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an...
A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an initially stationary cart of mass 0.40 kg. (A) If the carts stick together, what is their combined velocity immediately after the collision? (B) How much kinetic energy is lost in the collision?
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves toward second identical air cart that is at rest. When the carts collide, they stick together and move as one a) Using the conservation of linear momentum, calculate the velocity ve when the carts stick together (this is also the velocity of the center of mass after collision). b) Calculate the kinetic energy before and after collision. Is the collision elastic Without any calculation,...
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