Question

ANSWER ASAP PLEASE

Using only the standard input/output function fgetc(), define a C function, called int readInt(int *value), that reads an integer from the keyboard (stdin), stores it in *value and, returns 1 for success or 0 for fail (in case the user enters nondigit characters). In particular, readInt() reads all characters, one by one, until a blank (or newline) is encountered. The string is then converted to an integer. It is also possible to have the sign charcater (+/-) precedding the number

. Notes: • You need also to define a main() function that should look like the following one:

int main(int argc, char *argv[]){ : :

printf("Enter a first integer> ");

if (readInt(&n1))

printf("You enetered %d\n", n1);

else printf("Wrong input\n");

printf("Enter a secnd integer> ");

if (readInt(&n2))

printf("You enetered %d\n", n2); else printf("Wrong input\n");

printf("the sum of %d and %d is %d\n", n1, n2, n1+n2); exit(0); }

• Do not use any other function from the input/output standard library, and the string-to-integer conversion should be done using ASCII codes and multiplcations by 10.

Answer 1

solution:

#include <stdio.h>
int readInt(int *value)
{
//if value is a digit using assci 48 is 0 and 57 is 9 return 1
if(*value>=48 && *value<=57)
return 1;
else
return 0;
}
int main()
{
char ch,sign='+';
int p=0;
while(1)
{
fflush(stdin);//fflush to remove buffer
ch=fgetc(stdin);//read from keyboard
if(p==0)//checking for sign + or -
{
//if it is at starting and captures sign
if(ch=='-')
sign='-';
}
//we will read from keyoard untol we get ' ' or '\n'
if(ch==' '||ch=='\n')
break;
int n=ch;//make it as int
if(readInt(&n))//pass int pointer reference
{
p=p*10+(ch-'0');//if it is a number multiply and add the int value of char
}
else
{
printf("Not a digit");//else it is not a digit
}
  
}
//print the number conversion after wards
printf("\nThe number after conversion is %c%d",sign,p);
return 0;
}

output

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