A solenoid that is 68 cm long produces a magnetic field of 1.4 T within its core when it carries a current of 8.3 A .
How many turns of wire are contained in this solenoid?
Solution)
Given,
Length of solenoid, l = 68 cm = 0.68 m
Magnetic field, B =1.4T
Current , I=8.3A
Number of turns, N =?
We know ,
Bl =μoNI
So,
N = Bl/μ0*I
= (1.4)(0.68)/4*3.14*10^-7*8.3
=91320.69 turns= 91321 turns
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