H2C6H6O6
--------------------> HC6H6O6- +
H+
I 0.75 0 0
C -x +x +x
E (0.75-x) x x
Ka1 = [HC6H6O6-][H+]
8.0*10-5 = x2 / (0.75-x)
8.0*10-5 * (0.75-x) = x2
solving for x = 0.0078 M
so [HC6H6O6-] = [H+] = 0.0078 M
pH = -log[H+]
pH = -log[0.0078]
pH = 2.10
answer => pH = 2.1
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