The percentage by weight of nitric acid, HNO3, in a sample of concentrated nitric acid is to be determined.
a. Initially a NaOH solution was standardized by titration with a sample of potassium hydrogen phthalate, KHC8H4O4, a monoprotic acid often used as a primary standard. A sample of pure KHC8H4O4 weighing 1.518 grams was dissolved in water and titrated with the NaOH solution. To reach the equivalence point, 26.90 millilitres of base was required. Calculate the molarity of the NaOH solution. (Molecular weight: KHC8H4O4 = 204.2)
b. A 10.00 millilitre sample of the concentrated nitric acid was diluted with water to a total volume of 500.0 millilitres. Then 25.00 millilitres of the diluted acid solution was titrated with the standardized NaOH solution prepared in part (a). The equivalence point was reached after 28.35 millilitres of the base had been added. Calculate the molarity of the concentrated nitric acid.
The percentage by weight of nitric acid, HNO3, in a sample of concentrated nitric acid is...
The percentage by weight of nitric acid, HNO3, in a sample of concentrated nitric acid is to be determined. Initially a NaOH solution was standardized by titration with a sample of potassium hydrogen phthalate, KHC8H4O4, a monoprotic acid often used as a primary standard. A sample of pure KHC8H4O4 weighing 1.518 grams was dissolved in water and titrated with the NaOH solution. To reach the equivalence point, 26.90 millilitres of base was required. Calculate the molarity of the NaOH solution....
12.22 g of the monoprotic acid KHP(MW = 204.2 g/mol) is dissolved into water. The sample is titrated with a 0.85 M solution of calcium hydroxide to the equivalence point. What volume of base was used?
5. The Ka and Molar Mass of a Monoprotic Weak Acid a. Suppose that–unknown to you–the primary standard KHP (potassium hydrogen phthalate, KHC8H4O4) had a potassium iodide impurity of approximately one percent by mass. How would this have influenced the calculated molarity of your sodium hydroxide solution? Would your calculated value be too low, too high, or unchanged? Explain your answer. b. Sketch a typical titration curve for a monoprotic weak acid titrated with a strong base. Label the axes...
A volume of 20.05 mL of NaOH was used to titrate a 0.45 g sample of potassium hydrogen phthalate (KHP), a monoprotic acid, which has a molecular weight of 204.2 g/mol. Calculate the molarity of the NaOH solution. For the above titration of potassium hydrogen phthalate with NaOH, if you have the following pH indicators: methyl red, bromothymol blue, and phenolphthalein, which indicator should you use? Explain why.
A 14.50 mL sample of nitric acid (HNO3) is titrated to the end point by the addition of 10.45 mL of a 1.525 M solution of barium hydroxide (Ba(OH)2). What is the molarity of the nitric acid solution? (Balanced equation: 2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2 H20)
A sample of 0.2140 g of an unknown monoprotic acid was dissolved in 25.0 mL of water and titrated with 0.0950 M NaOH. The titration required 30.0 mL of base to reach the equivalence point, at which point the pH was 8.68. a) What is the molecular weight of the acid? b) What is the pKa of the acid?
You want to determine the concentration of acid in a particular solution. To this end, you decide to titrate the acid with a standardized sodium hydroxide solution. You quickly throw together an approximately 0.1 M NaOH solution, and then you realize you need to know the exact concentration of this solution before you can use it for anything meaningful. 1. Using an acid-base titration, 30.65 mL of your NaOH solution were needed to neutralize 0.6923 g of KHP (potassium hydrogen...
Solve the following 1) A solution is made by adding 24.8 mL of concentrated nitric acid (70.4 wt%, density 1.42 g/mL) to some water in a volumetric flask, and then adding water to the mark to make exactly 200 mL of solution. Calculate the concentration of this solution in molarity. 2) A 72.0 mL aliquot of a 1.50 M solution is diluted to a total volume of 288 mL. A 144 mL portion of that solution is diluted by adding...
a) A 25.00-mL sample of monoprotic acid was titrated with 0.0800 M potassium hydroxide solution. The equivalence point was reached after 18.75 mL of base was added. Calculate the concentration of the acid. b) A 15.00-mL sample of 0.120 M nitric acid was titrated with 0.0800 M potassium hydroxide. Calculate the pH of the sample when 10.00 mL of the base has been added.
5.00 mL of a solution containing a monoprotic acid was placed in a 100-mL volumetric flask, diluted to the mark with deionized water and mixed well. Then, 25.00 mL of this diluted acid solution was titrated with 0.08765 M NaOH. 9.23 mL of NaOH was required to reach the endpoint. a. What does the term monoprotic mean? b. Determine the molar ratio between the acid and NaOH. c. Calculate the moles of NaOH used in this titration. d. Calculate the...