Question

Use a Two-dimensional (3x3) array to solve the following problem:

Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive.

[10%] Display the array after the user inputs each value.

[10%] Documentation and the screen shot(s) of the results.

[70 %] Rotate/flip the array by changing places. Make the rows columns and vice versa.

[10%] Remember to validate the input and display an error message if the user inputs invalid data.

Example:

1 2 3

4 5 6

7 8 9

the result will be :

1 4 7

2 5 8

3 6 9

Answer 1

/* PROGRAM IN C++ */

#include<iostream>
using namespace std;
int main(){
   int a[3][3]; // declare array
   while(1){ // loop until correct matrix is not given
       cout<<"Enter Matrix (Number between 1 to 10): "<<endl; // message for input
       int flag = 0; // to check if number is valid
       for(int i = 0; i < 3; i++){ // outer loop (row)
           for(int j = 0; j < 3; j++){ // inner loop (column)
               cin >> a[i][j]; // input
               if(a[i][j] <= 0 || a[i][j] >= 11){ // check number under 1 to 10
                   cout<<"Invalid Value"<<endl;// message if not
                   flag = 1; // update flag to 1 if not
                   break; // break inner loop
               }      
           }
           if(flag == 1){ // also break outer loop
               break;
           }
       }
       if(flag == 0){ // if valid matrix entered break from while
           break;
       }  
   }
   cout<<"Input Matrix: "<<endl; // message
   for(int i = 0; i < 3; i++){ // print input matrix
       for(int j = 0; j < 3; j++){
           cout<<a[i][j]<<" ";
       }
       cout<<endl; // break line after 1 row
   }
   cout<<"\nOutput Matrix: "<<endl; // message for output matrix
   for(int i = 0; i < 3; i++){ // print output matrix
       for(int j = 0; j < 3; j++){
           cout<<a[j][i]<<" "; // transpose matrix
       }
       cout<<endl; // break after 1 row
   }  
  
}

/* OUTPUT */

/* PLEASE UPVOTE */