Question

Create a flowchart and a C++ program for the following problems:

1. Annual Salary: Workers at a particular company have won a 7.6% pay increase retroactive for six months.
Write a flowchart and C++ program that takes an employee’s previous annual salary as
input and outputs the amount of retroactive pay due the employee, the new annual salary,
and the new monthly salary. Use a variable declaration with the modifier const to express
the pay increase.

2. Extract the Digits: Create a flowchart and C++ program that would input a 5-digit number and then extract its
one’s digit , ten’s digit, hundred’s digit, thousand’s digit and ten thousand’s digit. Output the
extracted digits and output the digits in reverse order (you must use a formula in reversing
the order of the 5- digit number).
Example: Enter a 5-digit number: 23654
Output should be the following:
Ten Thousand’s Digit is 2
Thousand’s Digit is 3
Hundred’s Digit is 6
Ten’s Digit is 5
One’s Digit is 4
The reverse order is 45632

Answer 1

Answer 1:

Flowchart:

Code:

#include <iostream>

using namespace std;

int main() {
    const double payIncrease = 7.6 / 100;
    double annualSalary, retroactivePay, newAnnualSalary, newMonthlySalary;
    cout << "Enter previous annual salary: $";
    cin >> annualSalary;
    retroactivePay = annualSalary * payIncrease * 6 / 12;
    newMonthlySalary = annualSalary / 12 + retroactivePay / 6;
    newAnnualSalary = newMonthlySalary * 12;
    cout << "Retroactive pay: $" << retroactivePay << endl;
    cout << "New monthly salary: $" << newMonthlySalary << endl;
    cout << "New annual salary : $" << newAnnualSalary << endl;
    return 0;
}

Output:

Answer 2:

Flowchart:

Code:

#include <iostream>

using namespace std;

int main() {
    int num, nTenThousands, nThousands, nHundreds, nTens, nOnes, numReverse;

    cout << "Enter a 5-digit number: ";
    cin >> num;

    nOnes = num % 10;
    nTens = (num / 10) % 10;
    nHundreds = (num / 100) % 10;
    nThousands = (num / 1000) % 10;
    nTenThousands = num / 10000;
    numReverse = nOnes * 10000 + nTens * 1000 + nHundreds * 100 + nThousands * 10 + nTenThousands;

    cout << "Ten Thousand's Digit is " << nTenThousands << endl;
    cout << "Thousand's Digit is " << nThousands << endl;
    cout << "Hundred's Digit is " << nHundreds << endl;
    cout << "Ten's Digit is " << nTens << endl;
    cout << "One's Digit is " << nOnes << endl;
    cout << "The reverse order is " << numReverse << endl;
    return 0;
}

Output: