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A. look up the lowest energy electron pair arrangement for seven pairs of electrons in VSEPR...

A. look up the lowest energy electron pair arrangement for seven pairs of electrons in VSEPR and use the information to determine the structure lf (XeF5)^-. Name the structure

B. Assume incorrectly that d orbitald are energetically accedible to make hybrids in (XeF5)^-. Give Hybridization.

C. Assume Correctly that Xe d orbital are too high in energy to be used to make hybrids. With this assumption, give the valence bond description of XeF5^- by using sigma bond resonace.

D. What is the average Xe-F bond order based in VB description?
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Answer #1

A.

Name of the (XeF5)- is Xenon pentafluoride anion.

This molecule is having seven pairs of electrons. Among them, five pairs are bonding pairs forms Xe-F bonds and two pairs are lone pairs of electrons which not involving in the bonding.

We know from VSEPR theory, the structure of the molecule can determined by differences of electrostatic repulsion between bonding pairs and lone pairs involves in the molecule.

We know that, the order of repulsion is lone pair-lone pair>lone pair-bond pair>bond pair-bond pair.

Because, lone pairs are average closer to nucleus than bonding pair and more strongly repulse other electrons.

The structure of the (XeF5)- is pentagonal bipyramidal shape which is consider as parent shape with all seven pairs of electrons.

The two pairs of lone pair of electrons are kept in equatorial plane to reduce the repulsion of lone pair-lone pair electrons. As a result, the shape of the molecule is pentagonal planar.

i.e.,

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