Question

struct TempScale {
    double fahrenheit;
    double centigrade;
};

struct Reading {
    int windSpeed;
    double humidity;
    TempScale temperature;
};

Write a function called showReading. It should accept a Reading structure variable (see statement above) as its argument. The function should display the contents of the variable on the screen, written in C++

Answer 1

void showReading(struct Reading r){
   cout<<"windSpeed = "<<r.windSpeed<<endl;
   cout<<"humidity = "<<r.humidity<<endl;
   cout<<"temperature in fahrenheit = "<<r.temperature.fahrenheit<<endl;
   cout<<"temperature in centigrade = "<<r.temperature.centigrade<<endl;
}