A study showed that fourteen of 180 publicly traded business service companies failed a test for compliance with Sarbanes-Oxley requirements for financial records and fraud protection. Construct a 92% confidence interval for the population noncompliance proportion Select one: a. (0.039, 0.117) b. (0.043, 0.113) c. (0.051, 0.104) d. (0.045, 0.111)
part (b) Based on the confidence interval in part (a), can you conclude that the population noncompliance proportion is different than 11 percent? Select one: a. Yes, because 11% is not within the lower and upper limits of the confidence interval b. No, because 11% is within the lower and upper limits of the confidence interval c. Yes, because 11% is within the lower and upper limits of the confidence interval d. No, because 11% is not within the lower and upper limits of the confidence interval
part (c) If the number of sampled companies was decreased to 100 while everything else is still the same, what happens to the confidence interval in part (a)? Select one: a. It becomes wider due to larger margin of error b. Can't tell from given information c. It can either become narrower or wider d. It becomes narrower due to smaller margin of error
A study showed that fourteen of 180 publicly traded business service companies failed a test for...
12 A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requirements for financial records and fraud protection. Assuming that these are a random sample of all publicly traded companies, construct a 95% confidence interval for the overall noncompliance proportion. (Round your answers to 4 decimal places.) 2. points The 95% confidence interval is from 0.0390 x to 0.117
A public relations manager for the Cincinnati Reds wants to determine the percentage of local college students who attended a Reds baseball game at Great American Ballpark during the 2016 season. A sample of 648 students who are enrolled at a college or university within 25 miles of the Reds ballpark was asked whether or not they attended at least one Cincinnati Reds game during the 2016 season. Out of the 648 students asked, 246 had attended a game during...
A clinic offers a weight loss program. The table below gives the amounts of weight loss, in pounds, for a random sample of 20 of its clients at the conclusion of the program. Assume that the data are normally distributed. Complete parts (a) and (b). 9 B 10 B 23 17 13 19 16 24 15 11 17 7 10 22 24 18 15 The 99% confidence interval is from a lower limit of to an upper limit of (Round...
A random sample of 320 medical doctors showed that 180 had a solo practice. (a) Let p represent the proportion of all medical doctors who have a solo practice. Find a point estimate for p. (Use 3 decimal places.) (b) Find a 98% confidence interval for p. (Use 3 decimal places.) lower limit upper limit Give a brief explanation of the meaning of the interval. 98% of the all confidence intervals would include the true proportion of physicians with solo...
In a recent poll of 1 adults current debt during the next three months. A more detailed poll surveyed 1288 adult groups, 18-29, 30-49, 50-64, and 65+. Complete parts a and b below ) Do you expect the 95% confidence interval for the true proportion of all 18-to 29-year-olds who are wormed to be wider or narrower than the 95% c for the true proportion of all consumers? Explain Choose the correct answer below O A The interval for the...
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Potato Bruises
A sample of 150 potatos were spot checked for
bruises. "Yes" indicates that there were visible bruises.
Yes
To determine the total number of "Yes" answers, use
=countif(select data in column A, "Yes")
Yes
To determine the total number of "No" answers, use
=countif(select data in column A, "No")
Yes
Yes
x--the number of bruised potatos
Yes
n--sample size (total number of potatos checked)
Yes
point estimate (pbar)--x/n
Yes
z--use = - norm.s.inv((1-confidence level)/2)
Yes...
Question Help 0 Arandom sample of 20 purchases showed the amounts in the table in $). The mean is $47.86 and the standard deviation is $19.25. a) Construct a 80% confidence interval for the mean purchases of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be $20?...
A polling agency interviews 866 American adults and finds that 546 think licensed drivers should be required to retake their road test once they reach 65 years of age. Round all answers to 4 decimal places. 1. Calculate the point estimate for the proportion of American adults that think licensed drivers should be required to retake their road test once they reach 65 years of age. 2. Calculate the standard error for the point estimate you calculated in part 1. ...
Are you likely to purchase an item promoted by a celebrity on a social media site? According to a survey, 26% of social media users have made such a purchase. Complete parts (a) through (d) below. a. Suppose that the survey had a sample size of nequals1000. Construct a 90 % confidence interval estimate for the population proportion of social media users that have purchased an item promoted by a celebrity on a social media site. nothingless than or equalspiless...
In a random sample of 8 people, the mean commute time to work was 33.5 minutes and the standard deviation was 7 4 minutes A 90% confidence interval using the t-distribution was calculated to be (28.5,38.5). After researching commute times to work, it was found that the population standard deviation is 9 5 minutes Find the margin of error and construct a 90% confidence interval using the standard normal distribution with the appropriate calculations for a standard deviation that is...