A quality-control engineer of a high-tech company noted that 4% of all components provided by the company’s main supplier were of inferior quality (nonconforming items). Out of a sample of three hundred components provided by the supplier, what is the probability that more than 6% are defective?
|
0.0901 |
||
|
0.0764 |
||
|
0.0384 |
||
|
0.0708 |
||
|
None of the above |
Solution
Given that,
p = 0.04
1 - p = 1-0.04=0.96
n = 300

= p =0.04

=
[p(
1 - p ) / n] =
[(0.04*0.96) /300 ] = 0.01131
P(
> 0.06) = 1 - P(
<0.06 )
= 1 - P((
-
) /
< (0.06 -0.04) /0.01131 )
= 1 - P(z < 1.77)
Using z table
= 1 -0.9616
=0.0384
probability=0.0384
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