V = Q/C
That is, V is inversely proportional to C and C is given by, C = ekA/d, that is C is inversely proportional to plate separation d.
Thus V is directly proportional to d.
Thus the graph of voltage vs plate separation will be linear.
It will be linear for both the cases. Oly difference will be that for part b, the voltage value will be lesser.
How should my graph of voltage vs plate separation look like for a)without dielectric b) paper...
A dielectric-filled parallel-plate capacitor has plate area A = 20.0 cm2 , plate separation d = 8.00 mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 A) Find the energy U1 of the dielectric-filled capacitor B) The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2...
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A dielectric-filled parallel-plate capacitor has plate area A = 25.0 cm2 , plate separation d = 10.0 mm and dielectric constant k = 2.00. The capacitor is connected to a battery that creates a constant voltage V = 15.0 V . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 1. Find the energy U1 of the dielectric-filled capacitor. 2. The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy U2...
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