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two forces are applied to a tree stump to pull it out of the ground. fa...

two forces are applied to a tree stump to pull it out of the ground. fa magnitude of 2240 newtons and points 34 degrees south of east. fb has magnitude of 3160 newtons and points due south. find the magnitude and direction of the resultant force fa + fb that is applied to the stump. specify the direction with respect to due east. book gives answer of 4790 n and 67.2 degrees SE. I get answer of 4787 n and 67.2 degrees. using fax = 2240 x cos 34deg = 1857.044i and fay = 2240 x sin 34deg = -1252.592j and fb = -3160j . then -1252.592j - 3160j = 4412.592j Then sqrt of ((1857.044)sqrd + (4412.592)sqrd) = 4787.439n book gives 4790. can not figure out why the difference. angle tan-1(4412.592/1857.044)=-67.2 but the answer is a positive angle so do you subtract 67.2 from 360deg.

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