Question

A person with mass 55.0 kg stands d = 2.45 m away from the wall on a x = 5.70 m beam, as shown in figure d. The mass of the beam is 40.0 kg. Find the hinge force components and the tension in the wire.

T =  N

R_x =  N

R_y =  N

Answer 1

A)

mgx + Mg (L/2) - T sin(theta) L = 0

(55 x 9.8 x 2.45) + (40 x 9.8 x 5.7/2) = T sin(30) x 5.7

Tension, T = 855.35 N

B)

Horizontal component,

Fx = T cos(30) = 740.76 N

C)

Vertical component,

(55 x 9.8 x (5.7 - 2.45)) + (40 x 9.8 x 5.7/2) - Fy x 5.7 = 0

Fy = 503.32 N

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