1. For a standard normal random variable, nd a. P(Z < −1.13) b. P(−.87 < Z < 1.82) c. P(Z < −2.01 or Z > 3.21) d. P(|Z| > 1.28)
1. For a standard normal random variable, nd a. P(Z < −1.13) b. P(−.87 < Z...
Let Z be a standard normal random variable. Determine the value z such that P(Z > z) = a0.1003. b -1.04 c-0.65 d 0.75 c 1.28
Z is a standard normal random variable, then P =... a. P(Z < 1.37) = b. P(Z > −1.51) = c. P(−1.031 < Z < 1.92) = d. P(0.00 < Z < 1.79) = e. (A-Grade) P(Z = 0.518) =
1. Let Z be the standard normal random variable. Find (a) P(Z > −1.78) = (b) P(−.60 < Z < 1.25) = (c) z.005 = (d) z.025 =
IS Find the following probability for the standard normal random variable z. a. P(z<-1.02) b. P(z <2.03) c. P(0.68 szs2.03) d. P(-2.66szs1.56) a. P(z -1.02)(Round to four decimal places as needed.) b. Pize 2.03)=[] (Round to four decimal places as needed.) ook c. P(0.68 szs2.03) (Round to four decimal places as needed.) d.P(-2.66 s zs 1.56) = [□ (Round to four decimal places as needed.)
1. Given that z is a standard normal random variable, compute the following probabilities. a. P(Z < 1.38) b. P(z 2 1.32) c. P(-1.23 Sz5 1.23)
Find the probability of the standard normal random variable Z. P(Z < 1.49) A) 0.9319 B) 0.0681 C) 0.6879 D) 0.3121
Find the indicated probability given that Z is a random variable with a standard normal distribution. (Round your answer to four decimal places.) P(0 ≤ Z ≤ 1.28) P(0 ≤ Z ≤ 1.28) =
If Z is a standard normal random variable, then find: a. P(Z ≤ z), where z= 1.24 b. P(a ≤ Z ≤b), where a= 0.55 and b=1.33 c. find P(Z ≥ z), where z= 0.38 d. A value for z for which P(Z > z) = 0.8264
(1 point) Find the following probabilities for the standard normal random variable z. (a) P(-0.81 <<0.42) (b) P(-1.14 <z < 0.5) (c) P(Z < 0.69) a (d) P(Z > -0.6)
Assume that Z represents a standard normal random variable. (a) Find P(Z < 1.38) (b) Find P(Z > 2.02) (c) Find P(Z < -1.8) (d) Find P(0.42 < Z < 1.39) (e) Find c, so that P(Z < c) = 0.90