A projectile is launched at 20 m/s at an angle of 30o above the horizontal. Two seconds after the launch:
a. How fast is the object traveling?
b. In which direction is the object traveling (defined as an angle with respect to the horizontal).
Ans =
The velocity of the projectile after 2sec
Since there is no force acting in a horizontal direction so
horizontal velocity = initial horizontal velocity = VH = 20* cos 30 =17.3 m/s
The direction of object = tanθ = VV / VH = ( 20sin 30 - 10*2) / 17.3
tanθ = -0.57
θ = - 29.63 degree down from horizontal
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